100(1+x)^2=200

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Solution for 100(1+x)^2=200 equation: 



100(1+x)^2=200

We move all terms to the left:

100(1+x)^2-(200)=0

We add all the numbers together, and all the variables

100(x+1)^2-200=0

We move all terms containing x to the left, all other terms to the right

100(x+1)^2=200

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